0=x^2-135x+4

Solution for 0=x^2-135x+4 equation:

0=x^2-135x+4

We move all terms to the left:

0-(x^2-135x+4)=0

We add all the numbers together, and all the variables

-(x^2-135x+4)=0

We get rid of parentheses

-x^2+135x-4=0

We add all the numbers together, and all the variables

-1x^2+135x-4=0

a = -1; b = 135; c = -4;
Δ = b2-4ac
Δ = 1352-4·(-1)·(-4)
Δ = 18209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(135)-\sqrt{18209}}{2*-1}=\frac{-135-\sqrt{18209}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(135)+\sqrt{18209}}{2*-1}=\frac{-135+\sqrt{18209}}{-2}
$